Experiment for
Explaining Theorem of Pythagoras
STEP 1-
Take
a piece of paper and draw a right angle triangle in the middle of paper of sides base 3cm perpendicular 4 cm and hypotenuse 5 cm as
shown in fig.
STEP 2-
Make a square on all three sides of
triangle and make a grid in all three squares as shown in fig.
STEP 3-
Cut all the small squares of grid.
These small squares are equal areas so count the parts at each side and you'll
see number of small squares at base are 16 at perpendicular are 9 and at
hypotenuse 25 so the number of small squares at hypotenuse is equal to the sum
of number of small squares at base and
perpendicular.
No. of small squares at hypotenuse= No. of
small squares at base + No. of small squares at perpendicular
STEP 4-
And you'll see when you cut small
squares of base and perpendicular only and put on the grid on hypotenuse then
all the small squares of both sides are completely covered the grid at
hypotenuse .
So in this
triangle 52= 42
+ 32
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